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Old 24th April 2013, 09:27 PM   #1 (permalink)
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Engineering Maths

Can anyone explain to me about Domains and Ranges of function? My teacher sucks at explaining as he talks funny and do lots of weird motions when he is explaining it

P.S I'm from poly so idk if jc is the same as poly Engineering Maths

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Old 24th April 2013, 10:27 PM   #2 (permalink)
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Re: Engineering Maths

Domain is the set of permissible inputs of a function, range is the corresponding set of outputs.

Say f(x) = x^2, and domain is from -3 < x < 2. The range is therefore 0 ≤ x < 9.

I hope thats what you are looking for...

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Old 25th April 2013, 12:15 PM   #3 (permalink)
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Re: Engineering Maths

Originally Posted by aforl View Post
Domain is the set of permissible inputs of a function, range is the corresponding set of outputs.

Say f(x) = x^2, and domain is from -3 < x < 2. The range is therefore 0 ≤ x < 9.

I hope thats what you are looking for...
Aforl that is what I'm looking for but I still don't get it

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Old 25th April 2013, 12:37 PM   #4 (permalink)
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Re: Engineering Maths

You may be concentrating more on your teacher, rather than what she teaches you. Naughty guy...

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Old 25th April 2013, 01:51 PM   #5 (permalink)
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Re: Engineering Maths

Originally Posted by deathlight View Post
Aforl that is what I'm looking for but I still don't get it
Okay... Say, there's a function f(x) = 3x. 'Domain' refers to the set of permissible inputs. In this case, the input is x. So the domain of f(x) is therefore the set of x that can be entered into this function. Obviously the domain has no restrictions because x can be any real value and there is a corresponding f(x) for all x. Say, x = 4, f(x) = 12; x = -0.5, f(x) = -1.5 etc. Therefore, the range is all real values of f(x).

But of course you can choose to limit the domain to a particular set only. Say now, the domain of f(x) is restricted to 1 < x < 5. So now the range is therefore only 3 < f(x) < 15. The graph below shows the domain and the range of f(x), given by the grey and yellow portions respectively.



Now let's consider f(x) = x^2 - 1.

The domain can be x ∈ R (as in, x can be any real values). However in this case, it is obvious that f(x) cannot be less than 1. (Since x^2 must be positive). Therefore, the range is f(x) >= -1.

If you were to restrict the domain from -2 < x < 3, the corresponding range will therefore be -1 ≤ f(x) < 9. (see graph, when x varies from -2 to 3, the value of f(x) varies from -1 to 9)


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Old 26th April 2013, 03:33 PM   #6 (permalink)
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Re: Engineering Maths

Originally Posted by Jazzy23 View Post
You may be concentrating more on your teacher, rather than what she teaches you. Naughty guy...
My teacher is an old dude and he sucks a lot no one can understand what he teaches.

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Old 26th April 2013, 03:35 PM   #7 (permalink)
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Re: Engineering Maths

Originally Posted by aforl View Post
Okay... Say, there's a function f(x) = 3x. 'Domain' refers to the set of permissible inputs. In this case, the input is x. So the domain of f(x) is therefore the set of x that can be entered into this function. Obviously the domain has no restrictions because x can be any real value and there is a corresponding f(x) for all x. Say, x = 4, f(x) = 12; x = -0.5, f(x) = -1.5 etc. Therefore, the range is all real values of f(x).

But of course you can choose to limit the domain to a particular set only. Say now, the domain of f(x) is restricted to 1 < x < 5. So now the range is therefore only 3 < f(x) < 15. The graph below shows the domain and the range of f(x), given by the grey and yellow portions respectively.



Now let's consider f(x) = x^2 - 1.

The domain can be x ∈ R (as in, x can be any real values). However in this case, it is obvious that f(x) cannot be less than 1. (Since x^2 must be positive). Therefore, the range is f(x) >= -1.

If you were to restrict the domain from -2 < x < 3, the corresponding range will therefore be -1 ≤ f(x) < 9. (see graph, when x varies from -2 to 3, the value of f(x) varies from -1 to 9)

Oic it now thanks dude

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