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 Why aren't you a member of SGClub.com yet?? » Join 130,000+ other members in chatting. » Make lots of new friends here. » Keep up-to-date with current events. » Participate in Club outings. » Download lots of Free Stuff! Registration just takes 2mins and is absolutely free so join our community today! I Want to Choose my Own Personal Nickname Now! 28th April 2012, 06:56 PM #1 (permalink) Cool SGClubber  Posts: 259 Join Date: Dec 2009 Likes: 10 Liked 7 Times in 6 Posts Gender: Factor and Remainder Theorem Tweet Hi, I have two questions that I can't solve: Q1) Given that X - P is a factor of the expression X^2 - (P + 2)X - P^2 + 4P + 8, calculate the possible values of P A1) -2, 4 My Attempt: Let X^2 - (P+2)X - P^2 + 4P + 8 by f(x) f(P) = 0 (P)^2 - (P+2)(P) - P^2 + 4P + 8 = 0 P^2 - P^2 - 2P - P^2 + 4P + 8 = 0 -2P + 4P + 8 = 0 2P = -8 P = -4 I have no ideal why I keep getting -4 instead of two numbers Q2) A cubic equation f(x) = 0 has roots -3, -1 and 4. f(x) leaves a remainder of 12 when it is divided by x+2. Find the remainder when f(x) is divided by x^2-2x-1. A2) -16x - 20 My Attempt: (X+3)(X+1)(X-4) = 12 (X+3)(X^2-3X-4) = 12 X^3-3X^2-4X+3X^2-9X-12 = 12 X^3 -13X-12 = 12 X^3-13X-24 = 0 Division: X^3-13X-24 = 0 / x^2-2x-1 = -8x-22 Any help is appreciate, thanks Sponsors:    28th April 2012, 07:30 PM #2 (permalink) Jack Wilshere ❤      Posts: 6,043 Join Date: Jan 2010 Likes: 270 Liked 372 Times in 288 Posts Gender: Re: Factor and Remainder Theorem Tweet Originally Posted by danny2010 Hi, I have two questions that I can't solve: Q1) Given that X - P is a factor of the expression X^2 - (P + 2)X - P^2 + 4P + 8, calculate the possible values of P A1) -2, 4 My Attempt: Let X^2 - (P+2)X - P^2 + 4P + 8 by f(x) f(P) = 0 (P)^2 - (P+2)(P) - P^2 + 4P + 8 = 0 P^2 - P^2 - 2P - P^2 + 4P + 8 = 0 -2P + 4P + 8 = 0 2P = -8 P = -4 I have no ideal why I keep getting -4 instead of two numbers Where the blue -P^2 go? Lol. __________________ 생각하는중...    28th April 2012, 07:41 PM #3 (permalink) Jack Wilshere ❤      Posts: 6,043 Join Date: Jan 2010 Likes: 270 Liked 372 Times in 288 Posts Gender: Re: Factor and Remainder Theorem Tweet Q2) A cubic equation f(x) = 0 has roots -3, -1 and 4. f(x) leaves a remainder of 12 when it is divided by x+2. Find the remainder when f(x) is divided by x^2-2x-1. A2) -16x - 20 a(-2+3)(-2+1)(-2-4) = 12 a(1)(-1)(-6)=12 a=2 Thus f(x)= 2(X+3)(X+1)(X-4) Continue to divide and find the remainder. __________________ 생각하는중... Last edited by aforl; 28th April 2012 at 07:41 PM.   Members who Liked this post by aforl: namelessname (29th April 2012) 1st May 2012, 10:58 PM #4 (permalink) Cool SGClubber  Posts: 259 Join Date: Dec 2009 Likes: 10 Liked 7 Times in 6 Posts Gender: Re: Factor and Remainder Theorem Tweet Where the blue -P^2 go? Lol. I just subtract them together, P^2-P^2-P^2 = 0 since they are same term but I just realize that if I neutralize that first two P^2, I can shift that blue -P^2 over to the right hand side then the rest of the left hand side, I shift it to right hand side and factorize them, the answer is P=4 and P=-2, it is pretty weird. Thanks for your help!    2nd May 2012, 08:45 PM #5 (permalink) Addicted SGClubber  Posts: 874 Join Date: Sep 2010 Likes: 6 Liked 48 Times in 41 Posts Gender: Re: Factor and Remainder Theorem Tweet Originally Posted by danny2010 I just subtract them together, P^2-P^2-P^2 = 0 since they are same term but I just realize that if I neutralize that first two P^2, I can shift that blue -P^2 over to the right hand side then the rest of the left hand side, I shift it to right hand side and factorize them, the answer is P=4 and P=-2, it is pretty weird. Thanks for your help! Are you still thinking that P^2-P^2-P^2 = 0 ?!   Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post InfinityFrost Math Help 3 12th April 2012 11:15 AM tehlze Math Help 1 1st September 2009 12:53 PM KabutoEX Math Help 7 21st April 2009 06:47 PM sgcomics International & Singapore News 33 21st April 2009 01:43 PM Budfred School Life 14 1st February 2009 03:10 PM Featured Photos by marisoljames322 · · · Member Galleries 20359 photos13619 comments by marisoljames322 · · · Member Galleries 20359 photos13619 comments by pdsubbu · · · Member Galleries 20359 photos13619 comments by Vikas Dhar · · · Photography 35 photos36 comments by aaudreygan · · · Guy Photos 1581 photos946 comments by aaudreygan · · · Girl Photos 4351 photos28606 comments by a8paris · · · Guy Photos 1581 photos946 comments by a8paris · · · Guy Photos 1581 photos946 comments by aaricia · · · Girl Photos 4351 photos28606 comments by aaricia · · · Girl Photos 4351 photos28606 comments Copyright© 2004-2013 SGClub.com. All rights reserved.