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Old 5th August 2012, 02:43 PM   #1 (permalink)
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JC1 Integration Techniques tutorial question

It looks simple but I'M STUCK AT THIS QN!!!!!
I have no idea how to start
Can a kind soul attach the full solution T_T

(the 2nd image is the answer..)

THANKS IN ADVANCE!!!!!!!!!!!!! <3

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Last edited by -PINK; 5th August 2012 at 03:14 PM. Reason: solved it!
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Old 5th August 2012, 03:15 PM   #2 (permalink)
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Re: JC1 Integration Techniques tutorial question

OHHHH I SOLVED IT!! LOLOL

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Old 5th August 2012, 08:55 PM   #3 (permalink)
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Re: JC1 Integration Techniques tutorial question

∫ 1/(1+e^x) dx = ∫ 1 - e^x/(1+e^x) dx
= [x - ln(1+e^x)]
= 1 - ln(1+e) - 0 + ln 2
= 1 + ln (2/ (1+e))

Diff from your answer though.

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Old 5th August 2012, 09:32 PM   #4 (permalink)
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Re: JC1 Integration Techniques tutorial question

DoubleHellos is correct.

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Old 6th August 2012, 07:29 PM   #5 (permalink)
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Re: JC1 Integration Techniques tutorial question

Let me modify my answer a little,
from the last step:

1 + ln(2/(1+e)) = lne + ln(2/(1+e))
=ln(2e/(1+e))
=ln(2/(e^-1 + 1)) which is the answer, sorry i didn't manipulate to the final answer

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