A steel cable 3.04 cm^2 in cross-sectional area has a mass of 2.40 kg per meter of length. If 505 m of the cable is hung over a vertical cliff, how much does the cable stretch under its own weight? (Esteel = 2.00 x 10^11 N/m^2.)
Ans:4.95cm
using the eqn: Esteel = FL/Ax where x is the change in L.
F = weight of cable = 2.4 x 505 x 9.81
A is given, L is given.
So I just put in the values... get 9.9cm. where did I go wrong?
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thx that makes sense. so only half the length is being stretched
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that makes sense. so only half the length is being stretched
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